Base | Representation |
---|---|
bin | 111101011110010101… |
… | …0101101010010000101 |
3 | 110121202022020212022011 |
4 | 1322330222231102011 |
5 | 4130331132043023 |
6 | 140351353134221 |
7 | 12352303204345 |
oct | 1727452552205 |
9 | 417668225264 |
10 | 132014331013 |
11 | 50a94714904 |
12 | 217033ba371 |
13 | c5ab2c8b86 |
14 | 6564c14d25 |
15 | 3679b0750d |
hex | 1ebcaad485 |
132014331013 has 2 divisors, whose sum is σ = 132014331014. Its totient is φ = 132014331012.
The previous prime is 132014330969. The next prime is 132014331073. The reversal of 132014331013 is 310133410231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 85826733444 + 46187597569 = 292962^2 + 214913^2 .
It is an emirp because it is prime and its reverse (310133410231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132014331013 - 221 = 132012233861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132014331073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007165506 + 66007165507.
It is an arithmetic number, because the mean of its divisors is an integer number (66007165507).
Almost surely, 2132014331013 is an apocalyptic number.
It is an amenable number.
132014331013 is a deficient number, since it is larger than the sum of its proper divisors (1).
132014331013 is an equidigital number, since it uses as much as digits as its factorization.
132014331013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 132014331013 its reverse (310133410231), we get a palindrome (442147741244).
The spelling of 132014331013 in words is "one hundred thirty-two billion, fourteen million, three hundred thirty-one thousand, thirteen".
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