Base | Representation |
---|---|
bin | 11110000001000100000111… |
… | …110000111010110101001011 |
3 | 122022102110121021111210001012 |
4 | 132001010013300322311023 |
5 | 114300411234222312142 |
6 | 1144434350434314135 |
7 | 36543510240422312 |
oct | 3601040760726513 |
9 | 568373537453035 |
10 | 132014540041547 |
11 | 39078063272479 |
12 | 1298137642894b |
13 | 5887bc128cc27 |
14 | 2485775b41279 |
15 | 103e003cd1882 |
hex | 781107c3ad4b |
132014540041547 has 2 divisors, whose sum is σ = 132014540041548. Its totient is φ = 132014540041546.
The previous prime is 132014540041519. The next prime is 132014540041561. The reversal of 132014540041547 is 745140045410231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132014540041547 - 212 = 132014540037451 is a prime.
It is not a weakly prime, because it can be changed into another prime (132014540041597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007270020773 + 66007270020774.
It is an arithmetic number, because the mean of its divisors is an integer number (66007270020774).
Almost surely, 2132014540041547 is an apocalyptic number.
132014540041547 is a deficient number, since it is larger than the sum of its proper divisors (1).
132014540041547 is an equidigital number, since it uses as much as digits as its factorization.
132014540041547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 268800, while the sum is 41.
Adding to 132014540041547 its reverse (745140045410231), we get a palindrome (877154585451778).
The spelling of 132014540041547 in words is "one hundred thirty-two trillion, fourteen billion, five hundred forty million, forty-one thousand, five hundred forty-seven".
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