Search a number
-
+
132014540041561 is a prime number
BaseRepresentation
bin11110000001000100000111…
…110000111010110101011001
3122022102110121021111210001201
4132001010013300322311121
5114300411234222312221
61144434350434314201
736543510240422332
oct3601040760726531
9568373537453051
10132014540041561
1139078063272491
1212981376428961
135887bc128cc38
142485775b41289
15103e003cd1891
hex781107c3ad59

132014540041561 has 2 divisors, whose sum is σ = 132014540041562. Its totient is φ = 132014540041560.

The previous prime is 132014540041547. The next prime is 132014540041597. The reversal of 132014540041561 is 165140045410231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125209386090000 + 6805153951561 = 11189700^2 + 2608669^2 .

It is a cyclic number.

It is not a de Polignac number, because 132014540041561 - 223 = 132014531652953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132014540041561.

It is not a weakly prime, because it can be changed into another prime (132014540341561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007270020780 + 66007270020781.

It is an arithmetic number, because the mean of its divisors is an integer number (66007270020781).

Almost surely, 2132014540041561 is an apocalyptic number.

It is an amenable number.

132014540041561 is a deficient number, since it is larger than the sum of its proper divisors (1).

132014540041561 is an equidigital number, since it uses as much as digits as its factorization.

132014540041561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 132014540041561 its reverse (165140045410231), we get a palindrome (297154585451792).

The spelling of 132014540041561 in words is "one hundred thirty-two trillion, fourteen billion, five hundred forty million, forty-one thousand, five hundred sixty-one".