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132015013323134 = 2259126925473043
BaseRepresentation
bin11110000001000100100011…
…111110010110000101111110
3122022102111211021001222022212
4132001010203332112011332
5114300413221402320014
61144434505422340422
736543525045306104
oct3601044376260576
9568374737058285
10132015013323134
113907828643a987
1212981488a2a712
135887c6834b8c6
1424857bc93dc74
15103e03061d23e
hex781123f9617e

132015013323134 has 8 divisors (see below), whose sum is σ = 198022604177640. Its totient is φ = 66007478597256.

The previous prime is 132015013323113. The next prime is 132015013323161. The reversal of 132015013323134 is 431323310510231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 132015013323134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7553984 + ... + 17919059.

It is an arithmetic number, because the mean of its divisors is an integer number (24752825522205).

Almost surely, 2132015013323134 is an apocalyptic number.

132015013323134 is a deficient number, since it is larger than the sum of its proper divisors (66007590854506).

132015013323134 is a wasteful number, since it uses less digits than its factorization.

132015013323134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28064314.

The product of its (nonzero) digits is 19440, while the sum is 32.

Adding to 132015013323134 its reverse (431323310510231), we get a palindrome (563338323833365).

The spelling of 132015013323134 in words is "one hundred thirty-two trillion, fifteen billion, thirteen million, three hundred twenty-three thousand, one hundred thirty-four".

Divisors: 1 2 2591269 5182538 25473043 50946086 66007506661567 132015013323134