Base | Representation |
---|---|
bin | 10011001101011111000… |
… | …101111011100111111101 |
3 | 11200012112112210022100202 |
4 | 103031133011323213331 |
5 | 133112131442202313 |
6 | 2450245123333245 |
7 | 164243361554423 |
oct | 23153705734775 |
9 | 4605475708322 |
10 | 1320150350333 |
11 | 469966502691 |
12 | 193a2b821225 |
13 | 97649994569 |
14 | 47c7780b113 |
15 | 24517e8e558 |
hex | 1335f17b9fd |
1320150350333 has 2 divisors, whose sum is σ = 1320150350334. Its totient is φ = 1320150350332.
The previous prime is 1320150350293. The next prime is 1320150350417. The reversal of 1320150350333 is 3330530510231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1203064566649 + 117085783684 = 1096843^2 + 342178^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320150350333 - 224 = 1320133573117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320150350296 and 1320150350305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320150352333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660075175166 + 660075175167.
It is an arithmetic number, because the mean of its divisors is an integer number (660075175167).
Almost surely, 21320150350333 is an apocalyptic number.
It is an amenable number.
1320150350333 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320150350333 is an equidigital number, since it uses as much as digits as its factorization.
1320150350333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12150, while the sum is 29.
Adding to 1320150350333 its reverse (3330530510231), we get a palindrome (4650680860564).
The spelling of 1320150350333 in words is "one trillion, three hundred twenty billion, one hundred fifty million, three hundred fifty thousand, three hundred thirty-three".
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