Base | Representation |
---|---|
bin | 11110000001000100100110… |
… | …001110011101100100111011 |
3 | 122022102111220220011100220111 |
4 | 132001010212032131210323 |
5 | 114300413311040240043 |
6 | 1144434513252205151 |
7 | 36543526014365101 |
oct | 3601044616354473 |
9 | 568374826140814 |
10 | 132015051102523 |
11 | 390782a57a4116 |
12 | 129814996097b7 |
13 | 5887c73118784 |
14 | 24857c3975c71 |
15 | 103e033ad209d |
hex | 78112639d93b |
132015051102523 has 2 divisors, whose sum is σ = 132015051102524. Its totient is φ = 132015051102522.
The previous prime is 132015051102509. The next prime is 132015051102533. The reversal of 132015051102523 is 325201150510231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132015051102523 is a prime.
It is not a weakly prime, because it can be changed into another prime (132015051102533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007525551261 + 66007525551262.
It is an arithmetic number, because the mean of its divisors is an integer number (66007525551262).
Almost surely, 2132015051102523 is an apocalyptic number.
132015051102523 is a deficient number, since it is larger than the sum of its proper divisors (1).
132015051102523 is an equidigital number, since it uses as much as digits as its factorization.
132015051102523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 132015051102523 in words is "one hundred thirty-two trillion, fifteen billion, fifty-one million, one hundred two thousand, five hundred twenty-three".
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