Search a number
-
+
132015131 is a prime number
BaseRepresentation
bin1111101111001…
…10010000011011
3100012102001201022
413313212100123
5232243441011
621033313055
73162052523
oct767462033
9305361638
10132015131
1168578a16
123826578b
1321472a81
1413766683
15b8ca8db
hex7de641b

132015131 has 2 divisors, whose sum is σ = 132015132. Its totient is φ = 132015130.

The previous prime is 132015113. The next prime is 132015133. The reversal of 132015131 is 131510231.

Together with previous prime (132015113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132015131 - 214 = 131998747 is a prime.

It is a super-2 number, since 2×1320151312 = 34855989625894322, which contains 22 as substring.

Together with 132015133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132015133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007565 + 66007566.

It is an arithmetic number, because the mean of its divisors is an integer number (66007566).

Almost surely, 2132015131 is an apocalyptic number.

132015131 is a deficient number, since it is larger than the sum of its proper divisors (1).

132015131 is an equidigital number, since it uses as much as digits as its factorization.

132015131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 132015131 is about 11489.7837664597. The cubic root of 132015131 is about 509.1837911862.

Adding to 132015131 its reverse (131510231), we get a palindrome (263525362).

The spelling of 132015131 in words is "one hundred thirty-two million, fifteen thousand, one hundred thirty-one".