Base | Representation |
---|---|
bin | 11110000001000101000011… |
… | …000110000100000110111000 |
3 | 122022102120011122112021110010 |
4 | 132001011003012010012320 |
5 | 114300420304033042222 |
6 | 1144435033313221520 |
7 | 36543544015240446 |
oct | 3601050306040670 |
9 | 568376148467403 |
10 | 132015535440312 |
11 | 39078524133287 |
12 | 129815b38618a0 |
13 | 588801c578994 |
14 | 248582c011b96 |
15 | 103e0613a480c |
hex | 7811431841b8 |
132015535440312 has 16 divisors (see below), whose sum is σ = 330038838600840. Its totient is φ = 44005178480096.
The previous prime is 132015535440281. The next prime is 132015535440367. The reversal of 132015535440312 is 213044535510231.
It is a super-3 number, since 3×1320155354403123 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2750323654983 + ... + 2750323655030.
Almost surely, 2132015535440312 is an apocalyptic number.
132015535440312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132015535440312 is an abundant number, since it is smaller than the sum of its proper divisors (198023303160528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132015535440312 is a wasteful number, since it uses less digits than its factorization.
132015535440312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5500647310022 (or 5500647310018 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 39.
The spelling of 132015535440312 in words is "one hundred thirty-two trillion, fifteen billion, five hundred thirty-five million, four hundred forty thousand, three hundred twelve".
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