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132017021 is a prime number
BaseRepresentation
bin1111101111001…
…10101101111101
3100012102011022022
413313212231331
5232244021041
621033325525
73162061163
oct767465575
9305364268
10132017021
116857a384
12382668a5
13214738a6
1413767233
15b8cb24b
hex7de6b7d

132017021 has 2 divisors, whose sum is σ = 132017022. Its totient is φ = 132017020.

The previous prime is 132016981. The next prime is 132017029. The reversal of 132017021 is 120710231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105288121 + 26728900 = 10261^2 + 5170^2 .

It is a cyclic number.

It is not a de Polignac number, because 132017021 - 26 = 132016957 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132017029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66008510 + 66008511.

It is an arithmetic number, because the mean of its divisors is an integer number (66008511).

Almost surely, 2132017021 is an apocalyptic number.

It is an amenable number.

132017021 is a deficient number, since it is larger than the sum of its proper divisors (1).

132017021 is an equidigital number, since it uses as much as digits as its factorization.

132017021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 132017021 is about 11489.8660131439. The cubic root of 132017021 is about 509.1862210915.

Adding to 132017021 its reverse (120710231), we get a palindrome (252727252).

The spelling of 132017021 in words is "one hundred thirty-two million, seventeen thousand, twenty-one".