Base | Representation |
---|---|
bin | 11000100101110001… |
… | …10110001000100101 |
3 | 1021002001111121012112 |
4 | 30102320312020211 |
5 | 204014124343243 |
6 | 10022000130405 |
7 | 645103252043 |
oct | 142270661045 |
9 | 37061447175 |
10 | 13201793573 |
11 | 5665082a01 |
12 | 2685306a05 |
13 | 1325136497 |
14 | 8d3497393 |
15 | 524012818 |
hex | 312e36225 |
13201793573 has 2 divisors, whose sum is σ = 13201793574. Its totient is φ = 13201793572.
The previous prime is 13201793543. The next prime is 13201793593. The reversal of 13201793573 is 37539710231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6678485284 + 6523308289 = 81722^2 + 80767^2 .
It is a cyclic number.
It is not a de Polignac number, because 13201793573 - 28 = 13201793317 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13201793573.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201793533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600896786 + 6600896787.
It is an arithmetic number, because the mean of its divisors is an integer number (6600896787).
Almost surely, 213201793573 is an apocalyptic number.
It is an amenable number.
13201793573 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201793573 is an equidigital number, since it uses as much as digits as its factorization.
13201793573 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 119070, while the sum is 41.
The spelling of 13201793573 in words is "thirteen billion, two hundred one million, seven hundred ninety-three thousand, five hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •