Base | Representation |
---|---|
bin | 11110000001001001010011… |
… | …010110101110110101110111 |
3 | 122022102222221222121010210101 |
4 | 132001021103112232311313 |
5 | 114301004132410244112 |
6 | 1144441110444334531 |
7 | 36544065141535324 |
oct | 3601112326566567 |
9 | 568388858533711 |
10 | 132020103212407 |
11 | 3907a458563043 |
12 | 12982469544447 |
13 | 58885999c0bc7 |
14 | 2485b4291db4b |
15 | 103e22c3cd757 |
hex | 7812535aed77 |
132020103212407 has 2 divisors, whose sum is σ = 132020103212408. Its totient is φ = 132020103212406.
The previous prime is 132020103212317. The next prime is 132020103212489. The reversal of 132020103212407 is 704212301020231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132020103212407 - 219 = 132020102688119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132020173212407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010051606203 + 66010051606204.
It is an arithmetic number, because the mean of its divisors is an integer number (66010051606204).
Almost surely, 2132020103212407 is an apocalyptic number.
132020103212407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132020103212407 is an equidigital number, since it uses as much as digits as its factorization.
132020103212407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 132020103212407 its reverse (704212301020231), we get a palindrome (836232404232638).
The spelling of 132020103212407 in words is "one hundred thirty-two trillion, twenty billion, one hundred three million, two hundred twelve thousand, four hundred seven".
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