Base | Representation |
---|---|
bin | 11110000001001001011001… |
… | …001100001001111101110111 |
3 | 122022110000012210210111202011 |
4 | 132001021121030021331313 |
5 | 114301004332440300343 |
6 | 1144441124302425051 |
7 | 36544100440564306 |
oct | 3601113114117567 |
9 | 568400183714664 |
10 | 132020201103223 |
11 | 3907a4a8843944 |
12 | 12982496292187 |
13 | 58885b4076674 |
14 | 2485b5192243d |
15 | 103e235cb829d |
hex | 781259309f77 |
132020201103223 has 2 divisors, whose sum is σ = 132020201103224. Its totient is φ = 132020201103222.
The previous prime is 132020201103187. The next prime is 132020201103257. The reversal of 132020201103223 is 322301102020231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132020201103223 - 221 = 132020199006071 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132020201103194 and 132020201103203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132020201101223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010100551611 + 66010100551612.
It is an arithmetic number, because the mean of its divisors is an integer number (66010100551612).
Almost surely, 2132020201103223 is an apocalyptic number.
132020201103223 is a deficient number, since it is larger than the sum of its proper divisors (1).
132020201103223 is an equidigital number, since it uses as much as digits as its factorization.
132020201103223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 132020201103223 its reverse (322301102020231), we get a palindrome (454321303123454).
The spelling of 132020201103223 in words is "one hundred thirty-two trillion, twenty billion, two hundred one million, one hundred three thousand, two hundred twenty-three".
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