Base | Representation |
---|---|
bin | 11110000001001001011001… |
… | …110010010101110100001111 |
3 | 122022110000020111122001220012 |
4 | 132001021121302111310033 |
5 | 114301004343021110411 |
6 | 1144441125301143435 |
7 | 36544100621635100 |
oct | 3601113162256417 |
9 | 568400214561805 |
10 | 132020211113231 |
11 | 3907a503460581 |
12 | 129824996bab7b |
13 | 58885b616c94c |
14 | 2485b52daa3a7 |
15 | 103e236ae418b |
hex | 781259c95d0f |
132020211113231 has 24 divisors (see below), whose sum is σ = 156014532166464. Its totient is φ = 111368981687040.
The previous prime is 132020211113081. The next prime is 132020211113261. The reversal of 132020211113231 is 132311112020231.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-132020211113231 is a prime.
It is a super-2 number, since 2×1320202111132312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132020211113197 and 132020211113206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132020211113261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38201390 + ... + 41513691.
It is an arithmetic number, because the mean of its divisors is an integer number (6500605506936).
Almost surely, 2132020211113231 is an apocalyptic number.
132020211113231 is a deficient number, since it is larger than the sum of its proper divisors (23994321053233).
132020211113231 is an equidigital number, since it uses as much as digits as its factorization.
132020211113231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79715631 (or 79715624 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 132020211113231 its reverse (132311112020231), we get a palindrome (264331323133462).
The spelling of 132020211113231 in words is "one hundred thirty-two trillion, twenty billion, two hundred eleven million, one hundred thirteen thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •