Base | Representation |
---|---|
bin | 1100000000011101010111… |
… | …1101110010001110001011 |
3 | 1201202002201202202110122212 |
4 | 3000013111331302032023 |
5 | 3212300221201302412 |
6 | 44024532021135335 |
7 | 2531546316343616 |
oct | 300072575621613 |
9 | 51662652673585 |
10 | 13202024244107 |
11 | 422aa46567506 |
12 | 159278325a54b |
13 | 749c3a48ca6a |
14 | 338da4cb317d |
15 | 17d6356ac222 |
hex | c01d5f7238b |
13202024244107 has 2 divisors, whose sum is σ = 13202024244108. Its totient is φ = 13202024244106.
The previous prime is 13202024244103. The next prime is 13202024244137. The reversal of 13202024244107 is 70144242020231.
13202024244107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13202024244107 - 22 = 13202024244103 is a prime.
It is not a weakly prime, because it can be changed into another prime (13202024244103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601012122053 + 6601012122054.
It is an arithmetic number, because the mean of its divisors is an integer number (6601012122054).
Almost surely, 213202024244107 is an apocalyptic number.
13202024244107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202024244107 is an equidigital number, since it uses as much as digits as its factorization.
13202024244107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 13202024244107 its reverse (70144242020231), we get a palindrome (83346266264338).
The spelling of 13202024244107 in words is "thirteen trillion, two hundred two billion, twenty-four million, two hundred forty-four thousand, one hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •