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13202024244107 is a prime number
BaseRepresentation
bin1100000000011101010111…
…1101110010001110001011
31201202002201202202110122212
43000013111331302032023
53212300221201302412
644024532021135335
72531546316343616
oct300072575621613
951662652673585
1013202024244107
11422aa46567506
12159278325a54b
13749c3a48ca6a
14338da4cb317d
1517d6356ac222
hexc01d5f7238b

13202024244107 has 2 divisors, whose sum is σ = 13202024244108. Its totient is φ = 13202024244106.

The previous prime is 13202024244103. The next prime is 13202024244137. The reversal of 13202024244107 is 70144242020231.

13202024244107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13202024244107 - 22 = 13202024244103 is a prime.

It is not a weakly prime, because it can be changed into another prime (13202024244103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601012122053 + 6601012122054.

It is an arithmetic number, because the mean of its divisors is an integer number (6601012122054).

Almost surely, 213202024244107 is an apocalyptic number.

13202024244107 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202024244107 is an equidigital number, since it uses as much as digits as its factorization.

13202024244107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 32.

Adding to 13202024244107 its reverse (70144242020231), we get a palindrome (83346266264338).

The spelling of 13202024244107 in words is "thirteen trillion, two hundred two billion, twenty-four million, two hundred forty-four thousand, one hundred seven".