Base | Representation |
---|---|
bin | 1100000000011101011001… |
… | …1111111101100000101011 |
3 | 1201202002202101121122021201 |
4 | 3000013112133331200223 |
5 | 3212300231000000433 |
6 | 44024532541145031 |
7 | 2531546455446553 |
oct | 300072637754053 |
9 | 51662671548251 |
10 | 13202033203243 |
11 | 422aa50626655 |
12 | 159278625b177 |
13 | 749c3c2a8921 |
14 | 338da6166163 |
15 | 17d63637ba7d |
hex | c01d67fd82b |
13202033203243 has 2 divisors, whose sum is σ = 13202033203244. Its totient is φ = 13202033203242.
The previous prime is 13202033203241. The next prime is 13202033203277. The reversal of 13202033203243 is 34230233020231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13202033203243 - 21 = 13202033203241 is a prime.
Together with 13202033203241, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13202033203241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601016601621 + 6601016601622.
It is an arithmetic number, because the mean of its divisors is an integer number (6601016601622).
Almost surely, 213202033203243 is an apocalyptic number.
13202033203243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202033203243 is an equidigital number, since it uses as much as digits as its factorization.
13202033203243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 13202033203243 its reverse (34230233020231), we get a palindrome (47432266223474).
The spelling of 13202033203243 in words is "thirteen trillion, two hundred two billion, thirty-three million, two hundred three thousand, two hundred forty-three".
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