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132020597 is a prime number
BaseRepresentation
bin1111101111001…
…11100101110101
3100012102100012202
413313213211311
5232244124342
621033354245
73162104462
oct767474565
9305370182
10132020597
1168582035
1238268985
13214753c7
1413768669
15b8cc332
hex7de7975

132020597 has 2 divisors, whose sum is σ = 132020598. Its totient is φ = 132020596.

The previous prime is 132020579. The next prime is 132020611. The reversal of 132020597 is 795020231.

Together with previous prime (132020579) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114789796 + 17230801 = 10714^2 + 4151^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132020597 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132020507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010298 + 66010299.

It is an arithmetic number, because the mean of its divisors is an integer number (66010299).

Almost surely, 2132020597 is an apocalyptic number.

It is an amenable number.

132020597 is a deficient number, since it is larger than the sum of its proper divisors (1).

132020597 is an equidigital number, since it uses as much as digits as its factorization.

132020597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 29.

The square root of 132020597 is about 11490.0216274818. The cubic root of 132020597 is about 509.1908185630.

The spelling of 132020597 in words is "one hundred thirty-two million, twenty thousand, five hundred ninety-seven".