Base | Representation |
---|---|
bin | 10011001101100010101… |
… | …001111001101011110100 |
3 | 11200012200201020110212221 |
4 | 103031202221321223310 |
5 | 133112242242024340 |
6 | 2450255100252124 |
7 | 164245015534420 |
oct | 23154251715364 |
9 | 4605621213787 |
10 | 1320210111220 |
11 | 46999720a950 |
12 | 193a47841044 |
13 | 97659189730 |
14 | 47c81725b80 |
15 | 2451d34644a |
hex | 13362a79af4 |
1320210111220 has 384 divisors, whose sum is σ = 3799754219520. Its totient is φ = 371978680320.
The previous prime is 1320210111131. The next prime is 1320210111223. The reversal of 1320210111220 is 221110120231.
It is a junction number, because it is equal to n+sod(n) for n = 1320210111194 and 1320210111203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320210111223) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 890228599 + ... + 890230081.
It is an arithmetic number, because the mean of its divisors is an integer number (9895193280).
Almost surely, 21320210111220 is an apocalyptic number.
1320210111220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1320210111220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1899877109760).
1320210111220 is an abundant number, since it is smaller than the sum of its proper divisors (2479544108300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1320210111220 is a wasteful number, since it uses less digits than its factorization.
1320210111220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2415 (or 2413 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1320210111220 its reverse (221110120231), we get a palindrome (1541320231451).
The spelling of 1320210111220 in words is "one trillion, three hundred twenty billion, two hundred ten million, one hundred eleven thousand, two hundred twenty".
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