Search a number
-
+
13202140401312 = 25353229105110781
BaseRepresentation
bin1100000000011101110011…
…1000111000111010100000
31201202010000212022212101120
43000013130320320322200
53212300440420320222
644024551330532240
72531552226561432
oct300073470707240
951663025285346
1013202140401312
11422aaa60940a5
1215927b6137080
13749c5856c835
14338db64ac652
1517d6409a415c
hexc01dce38ea0

13202140401312 has 192 divisors, whose sum is σ = 35500723493760. Its totient is φ = 4294338048000.

The previous prime is 13202140401251. The next prime is 13202140401313. The reversal of 13202140401312 is 21310404120231.

It is a super-3 number, since 3×132021404013123 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is not an unprimeable number, because it can be changed into a prime (13202140401313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1224569362 + ... + 1224580142.

It is an arithmetic number, because the mean of its divisors is an integer number (184899601530).

Almost surely, 213202140401312 is an apocalyptic number.

13202140401312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13202140401312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17750361746880).

13202140401312 is an abundant number, since it is smaller than the sum of its proper divisors (22298583092448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13202140401312 is a wasteful number, since it uses less digits than its factorization.

13202140401312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12127 (or 12119 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13202140401312 its reverse (21310404120231), we get a palindrome (34512544521543).

The spelling of 13202140401312 in words is "thirteen trillion, two hundred two billion, one hundred forty million, four hundred one thousand, three hundred twelve".