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1320214223957 is a prime number
BaseRepresentation
bin10011001101100010111…
…001100101110001010101
311200012200222222102111112
4103031202321211301111
5133112244320131312
62450255324344405
7164245065514046
oct23154271456125
94605628872445
101320214223957
11469999569902
12193a490a5105
1397659c996c5
1447c820b68cd
152451d8a9d22
hex13362e65c55

1320214223957 has 2 divisors, whose sum is σ = 1320214223958. Its totient is φ = 1320214223956.

The previous prime is 1320214223947. The next prime is 1320214223963. The reversal of 1320214223957 is 7593224120231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1054562632561 + 265651591396 = 1026919^2 + 515414^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320214223957 - 212 = 1320214219861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320214223947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660107111978 + 660107111979.

It is an arithmetic number, because the mean of its divisors is an integer number (660107111979).

Almost surely, 21320214223957 is an apocalyptic number.

It is an amenable number.

1320214223957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320214223957 is an equidigital number, since it uses as much as digits as its factorization.

1320214223957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 1320214223957 in words is "one trillion, three hundred twenty billion, two hundred fourteen million, two hundred twenty-three thousand, nine hundred fifty-seven".