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13202144043000 = 23353111914194999
BaseRepresentation
bin1100000000011101110100…
…0110110001111111111000
31201202010001010011212211220
43000013131012301333320
53212300442333334000
644024551540552040
72531552302536543
oct300073506617770
951663033155756
1013202144043000
11422aaa8151160
1215927b73b2620
13749c59246293
14338db6b7985a
1517d640e731a0
hexc01dd1b1ff8

13202144043000 has 512 divisors, whose sum is σ = 45287424000000. Its totient is φ = 3175529280000.

The previous prime is 13202144042999. The next prime is 13202144043007. The reversal of 13202144043000 is 34044120231.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13202144043007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2640954501 + ... + 2640959499.

It is an arithmetic number, because the mean of its divisors is an integer number (88452000000).

Almost surely, 213202144043000 is an apocalyptic number.

13202144043000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13202144043000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22643712000000).

13202144043000 is an abundant number, since it is smaller than the sum of its proper divisors (32085279957000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13202144043000 is a wasteful number, since it uses less digits than its factorization.

13202144043000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5644 (or 5630 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13202144043000 its reverse (34044120231), we get a palindrome (13236188163231).

The spelling of 13202144043000 in words is "thirteen trillion, two hundred two billion, one hundred forty-four million, forty-three thousand".