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132022121220173 is a prime number
BaseRepresentation
bin11110000001001011001011…
…101000110100100001001101
3122022110012011121211120000202
4132001023023220310201031
5114301022301013021143
61144442043013303245
736544166144401022
oct3601131350644115
9568405147746022
10132022121220173
11390802a368a158
1212982931334b25
13588882bb01942
142485c94945549
15103e2e964bab8
hex7812cba3484d

132022121220173 has 2 divisors, whose sum is σ = 132022121220174. Its totient is φ = 132022121220172.

The previous prime is 132022121220169. The next prime is 132022121220323. The reversal of 132022121220173 is 371022121220231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121750435947364 + 10271685272809 = 11034058^2 + 3204947^2 .

It is a cyclic number.

It is not a de Polignac number, because 132022121220173 - 22 = 132022121220169 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132022121225173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011060610086 + 66011060610087.

It is an arithmetic number, because the mean of its divisors is an integer number (66011060610087).

Almost surely, 2132022121220173 is an apocalyptic number.

It is an amenable number.

132022121220173 is a deficient number, since it is larger than the sum of its proper divisors (1).

132022121220173 is an equidigital number, since it uses as much as digits as its factorization.

132022121220173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

The spelling of 132022121220173 in words is "one hundred thirty-two trillion, twenty-two billion, one hundred twenty-one million, two hundred twenty thousand, one hundred seventy-three".