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1320224220257 is a prime number
BaseRepresentation
bin10011001101100011011…
…111101110010001100001
311200012201200210021211212
4103031203133232101201
5133112304400022012
62450300322515505
7164245246466555
oct23154337562141
94605650707755
101320224220257
114699a4177208
12193a50505b95
139765c089687
1447c83559865
152451e6d1b22
hex133637ee461

1320224220257 has 2 divisors, whose sum is σ = 1320224220258. Its totient is φ = 1320224220256.

The previous prime is 1320224220221. The next prime is 1320224220283. The reversal of 1320224220257 is 7520224220231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1116750151696 + 203474068561 = 1056764^2 + 451081^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320224220257 - 216 = 1320224154721 is a prime.

It is not a weakly prime, because it can be changed into another prime (1320224229257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660112110128 + 660112110129.

It is an arithmetic number, because the mean of its divisors is an integer number (660112110129).

Almost surely, 21320224220257 is an apocalyptic number.

It is an amenable number.

1320224220257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320224220257 is an equidigital number, since it uses as much as digits as its factorization.

1320224220257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 32.

Adding to 1320224220257 its reverse (7520224220231), we get a palindrome (8840448440488).

The spelling of 1320224220257 in words is "one trillion, three hundred twenty billion, two hundred twenty-four million, two hundred twenty thousand, two hundred fifty-seven".