Base | Representation |
---|---|
bin | 10011001101100011011… |
… | …111101110010001100001 |
3 | 11200012201200210021211212 |
4 | 103031203133232101201 |
5 | 133112304400022012 |
6 | 2450300322515505 |
7 | 164245246466555 |
oct | 23154337562141 |
9 | 4605650707755 |
10 | 1320224220257 |
11 | 4699a4177208 |
12 | 193a50505b95 |
13 | 9765c089687 |
14 | 47c83559865 |
15 | 2451e6d1b22 |
hex | 133637ee461 |
1320224220257 has 2 divisors, whose sum is σ = 1320224220258. Its totient is φ = 1320224220256.
The previous prime is 1320224220221. The next prime is 1320224220283. The reversal of 1320224220257 is 7520224220231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1116750151696 + 203474068561 = 1056764^2 + 451081^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320224220257 - 216 = 1320224154721 is a prime.
It is not a weakly prime, because it can be changed into another prime (1320224229257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660112110128 + 660112110129.
It is an arithmetic number, because the mean of its divisors is an integer number (660112110129).
Almost surely, 21320224220257 is an apocalyptic number.
It is an amenable number.
1320224220257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320224220257 is an equidigital number, since it uses as much as digits as its factorization.
1320224220257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 32.
Adding to 1320224220257 its reverse (7520224220231), we get a palindrome (8840448440488).
The spelling of 1320224220257 in words is "one trillion, three hundred twenty billion, two hundred twenty-four million, two hundred twenty thousand, two hundred fifty-seven".
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