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132022531251097 is a prime number
BaseRepresentation
bin11110000001001011100100…
…000100111101101110011001
3122022110020020012101021201021
4132001023210010331232121
5114301024121000013342
61144442151421522441
736544212253531324
oct3601134404755631
9568406205337637
10132022531251097
1139080494086493
1212982a26713421
135888895a45ba6
142485cd319b7bb
15103e320642567
hex7812e413db99

132022531251097 has 2 divisors, whose sum is σ = 132022531251098. Its totient is φ = 132022531251096.

The previous prime is 132022531251089. The next prime is 132022531251109. The reversal of 132022531251097 is 790152135220231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124210668360256 + 7811862890841 = 11144984^2 + 2794971^2 .

It is a cyclic number.

It is not a de Polignac number, because 132022531251097 - 23 = 132022531251089 is a prime.

It is not a weakly prime, because it can be changed into another prime (132022531251007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011265625548 + 66011265625549.

It is an arithmetic number, because the mean of its divisors is an integer number (66011265625549).

Almost surely, 2132022531251097 is an apocalyptic number.

It is an amenable number.

132022531251097 is a deficient number, since it is larger than the sum of its proper divisors (1).

132022531251097 is an equidigital number, since it uses as much as digits as its factorization.

132022531251097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 132022531251097 in words is "one hundred thirty-two trillion, twenty-two billion, five hundred thirty-one million, two hundred fifty-one thousand, ninety-seven".