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132022531251007 is a prime number
BaseRepresentation
bin11110000001001011100100…
…000100111101101100111111
3122022110020020012101021120221
4132001023210010331230333
5114301024121000013012
61144442151421522211
736544212253531135
oct3601134404755477
9568406205337527
10132022531251007
1139080494086411
1212982a26713367
135888895a45b37
142485cd319b755
15103e320642507
hex7812e413db3f

132022531251007 has 2 divisors, whose sum is σ = 132022531251008. Its totient is φ = 132022531251006.

The previous prime is 132022531250927. The next prime is 132022531251047. The reversal of 132022531251007 is 700152135220231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132022531251007 - 27 = 132022531250879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132022531251047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011265625503 + 66011265625504.

It is an arithmetic number, because the mean of its divisors is an integer number (66011265625504).

Almost surely, 2132022531251007 is an apocalyptic number.

132022531251007 is a deficient number, since it is larger than the sum of its proper divisors (1).

132022531251007 is an equidigital number, since it uses as much as digits as its factorization.

132022531251007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 132022531251007 its reverse (700152135220231), we get a palindrome (832174666471238).

The spelling of 132022531251007 in words is "one hundred thirty-two trillion, twenty-two billion, five hundred thirty-one million, two hundred fifty-one thousand, seven".