Base | Representation |
---|---|
bin | 1100000000011110011001… |
… | …1001101110001110011011 |
3 | 1201202010102222122111001121 |
4 | 3000013212121232032123 |
5 | 3212301302300100402 |
6 | 44025015231430111 |
7 | 2531556205302226 |
oct | 300074631561633 |
9 | 51663388574047 |
10 | 13202300003227 |
11 | 4230078194405 |
12 | 159283b685337 |
13 | 749c8265103a |
14 | 338dcd7765bd |
15 | 17d64e9cd837 |
hex | c01e666e39b |
13202300003227 has 2 divisors, whose sum is σ = 13202300003228. Its totient is φ = 13202300003226.
The previous prime is 13202300003213. The next prime is 13202300003267. The reversal of 13202300003227 is 72230000320231.
13202300003227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13202300003227 - 211 = 13202300001179 is a prime.
It is not a weakly prime, because it can be changed into another prime (13202300003267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601150001613 + 6601150001614.
It is an arithmetic number, because the mean of its divisors is an integer number (6601150001614).
Almost surely, 213202300003227 is an apocalyptic number.
13202300003227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202300003227 is an equidigital number, since it uses as much as digits as its factorization.
13202300003227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 25.
Adding to 13202300003227 its reverse (72230000320231), we get a palindrome (85432300323458).
The spelling of 13202300003227 in words is "thirteen trillion, two hundred two billion, three hundred million, three thousand, two hundred twenty-seven".
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