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1320231331169 is a prime number
BaseRepresentation
bin10011001101100011111…
…010110110010101100001
311200012202012011120011222
4103031203322312111201
5133112313210044134
62450301135144425
7164245364104232
oct23154372662541
94605665146158
101320231331169
114699a81937a3
12193a52975115
13976606a920a
1447c8448b089
1524520138a2e
hex13363eb6561

1320231331169 has 2 divisors, whose sum is σ = 1320231331170. Its totient is φ = 1320231331168.

The previous prime is 1320231331141. The next prime is 1320231331213. The reversal of 1320231331169 is 9611331320231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1313992227025 + 6239104144 = 1146295^2 + 78988^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320231331169 is a prime.

It is a super-2 number, since 2×13202313311692 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1320231331109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660115665584 + 660115665585.

It is an arithmetic number, because the mean of its divisors is an integer number (660115665585).

Almost surely, 21320231331169 is an apocalyptic number.

It is an amenable number.

1320231331169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320231331169 is an equidigital number, since it uses as much as digits as its factorization.

1320231331169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 35.

The spelling of 1320231331169 in words is "one trillion, three hundred twenty billion, two hundred thirty-one million, three hundred thirty-one thousand, one hundred sixty-nine".