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1320231331141 is a prime number
BaseRepresentation
bin10011001101100011111…
…010110110010101000101
311200012202012011120010221
4103031203322312111011
5133112313210044031
62450301135144341
7164245364104162
oct23154372662505
94605665146127
101320231331141
114699a8193778
12193a529750b1
13976606a91b8
1447c8448b069
1524520138a11
hex13363eb6545

1320231331141 has 2 divisors, whose sum is σ = 1320231331142. Its totient is φ = 1320231331140.

The previous prime is 1320231331117. The next prime is 1320231331169. The reversal of 1320231331141 is 1411331320231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 929143694241 + 391087636900 = 963921^2 + 625370^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320231331141 - 25 = 1320231331109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320231334141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660115665570 + 660115665571.

It is an arithmetic number, because the mean of its divisors is an integer number (660115665571).

Almost surely, 21320231331141 is an apocalyptic number.

It is an amenable number.

1320231331141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320231331141 is an equidigital number, since it uses as much as digits as its factorization.

1320231331141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1320231331141 its reverse (1411331320231), we get a palindrome (2731562651372).

The spelling of 1320231331141 in words is "one trillion, three hundred twenty billion, two hundred thirty-one million, three hundred thirty-one thousand, one hundred forty-one".