Base | Representation |
---|---|
bin | 1111101111010… |
… | …00001101101011 |
3 | 100012102110201012 |
4 | 13313220031223 |
5 | 232244220042 |
6 | 21033414135 |
7 | 3162115064 |
oct | 767501553 |
9 | 305373635 |
10 | 132023147 |
11 | 68583a43 |
12 | 3826a34b |
13 | 21476609 |
14 | 1376956b |
15 | b8cce82 |
hex | 7de836b |
132023147 has 2 divisors, whose sum is σ = 132023148. Its totient is φ = 132023146.
The previous prime is 132023117. The next prime is 132023149. The reversal of 132023147 is 741320231.
It is a strong prime.
It is an emirp because it is prime and its reverse (741320231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132023147 - 212 = 132019051 is a prime.
It is a super-2 number, since 2×1320231472 = 34860222687567218, which contains 22 as substring.
Together with 132023149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132023149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011573 + 66011574.
It is an arithmetic number, because the mean of its divisors is an integer number (66011574).
Almost surely, 2132023147 is an apocalyptic number.
132023147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132023147 is an equidigital number, since it uses as much as digits as its factorization.
132023147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 23.
The square root of 132023147 is about 11490.1325927946. The cubic root of 132023147 is about 509.1940969106.
Adding to 132023147 its reverse (741320231), we get a palindrome (873343378).
The spelling of 132023147 in words is "one hundred thirty-two million, twenty-three thousand, one hundred forty-seven".
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