Base | Representation |
---|---|
bin | 1100000000011110100000… |
… | …1101010101110101110011 |
3 | 1201202010112002200022221122 |
4 | 3000013220031111311303 |
5 | 3212301333024441201 |
6 | 44025022233212455 |
7 | 2531560024025156 |
oct | 300075015256563 |
9 | 51663462608848 |
10 | 13202330312051 |
11 | 4230093305921 |
12 | 159284986112b |
13 | 749c88a0375a |
14 | 338dd37c5c9d |
15 | 17d6524b8e1b |
hex | c01e8355d73 |
13202330312051 has 2 divisors, whose sum is σ = 13202330312052. Its totient is φ = 13202330312050.
The previous prime is 13202330311979. The next prime is 13202330312053. The reversal of 13202330312051 is 15021303320231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13202330312051 is a prime.
Together with 13202330312053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13202330312051.
It is not a weakly prime, because it can be changed into another prime (13202330312053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601165156025 + 6601165156026.
It is an arithmetic number, because the mean of its divisors is an integer number (6601165156026).
Almost surely, 213202330312051 is an apocalyptic number.
13202330312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202330312051 is an equidigital number, since it uses as much as digits as its factorization.
13202330312051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 13202330312051 its reverse (15021303320231), we get a palindrome (28223633632282).
The spelling of 13202330312051 in words is "thirteen trillion, two hundred two billion, three hundred thirty million, three hundred twelve thousand, fifty-one".
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