Base | Representation |
---|---|
bin | 11110000001001100010010… |
… | …101000001000010000111111 |
3 | 122022110022020121220200100122 |
4 | 132001030102220020100333 |
5 | 114301032220412034442 |
6 | 1144442401120445155 |
7 | 36544240515626246 |
oct | 3601142250102077 |
9 | 568408217820318 |
10 | 132023312221247 |
11 | 390808549a9967 |
12 | 129830041797bb |
13 | 588898b7950c5 |
14 | 2485d68bb195d |
15 | 103e368eaadd2 |
hex | 781312a0843f |
132023312221247 has 2 divisors, whose sum is σ = 132023312221248. Its totient is φ = 132023312221246.
The previous prime is 132023312221169. The next prime is 132023312221261. The reversal of 132023312221247 is 742122213320231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132023312221247 - 218 = 132023311959103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132023312221147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011656110623 + 66011656110624.
It is an arithmetic number, because the mean of its divisors is an integer number (66011656110624).
Almost surely, 2132023312221247 is an apocalyptic number.
132023312221247 is a deficient number, since it is larger than the sum of its proper divisors (1).
132023312221247 is an equidigital number, since it uses as much as digits as its factorization.
132023312221247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 132023312221247 its reverse (742122213320231), we get a palindrome (874145525541478).
The spelling of 132023312221247 in words is "one hundred thirty-two trillion, twenty-three billion, three hundred twelve million, two hundred twenty-one thousand, two hundred forty-seven".
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