Base | Representation |
---|---|
bin | 10011001101100100000… |
… | …010000011110000000111 |
3 | 11200012202022201120201102 |
4 | 103031210002003300013 |
5 | 133112314201034002 |
6 | 2450301243450315 |
7 | 164245416135302 |
oct | 23154402036007 |
9 | 4605668646642 |
10 | 1320233221127 |
11 | 4699a9264747 |
12 | 193a5352699b |
13 | 97660bbb532 |
14 | 47c8481db39 |
15 | 245203ada02 |
hex | 13364083c07 |
1320233221127 has 2 divisors, whose sum is σ = 1320233221128. Its totient is φ = 1320233221126.
The previous prime is 1320233221117. The next prime is 1320233221201. The reversal of 1320233221127 is 7211223320231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1320233221127 - 212 = 1320233217031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1320233221127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320233221117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660116610563 + 660116610564.
It is an arithmetic number, because the mean of its divisors is an integer number (660116610564).
Almost surely, 21320233221127 is an apocalyptic number.
1320233221127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320233221127 is an equidigital number, since it uses as much as digits as its factorization.
1320233221127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 1320233221127 its reverse (7211223320231), we get a palindrome (8531456541358).
The spelling of 1320233221127 in words is "one trillion, three hundred twenty billion, two hundred thirty-three million, two hundred twenty-one thousand, one hundred twenty-seven".
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