Base | Representation |
---|---|
bin | 10011001101100100000… |
… | …110100110100100101111 |
3 | 11200012202101222002202020 |
4 | 103031210012212210233 |
5 | 133112320002143320 |
6 | 2450301325201223 |
7 | 164245432226226 |
oct | 23154406464457 |
9 | 4605671862666 |
10 | 1320234412335 |
11 | 4699a99a8713 |
12 | 193a53a00213 |
13 | 976612177a7 |
14 | 47c84a4dcbd |
15 | 24520546940 |
hex | 133641a692f |
1320234412335 has 32 divisors (see below), whose sum is σ = 2148027932160. Its totient is φ = 692339356800.
The previous prime is 1320234412309. The next prime is 1320234412337. The reversal of 1320234412335 is 5332144320231.
It is not a de Polignac number, because 1320234412335 - 213 = 1320234404143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320234412296 and 1320234412305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320234412337) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2867811 + ... + 3296180.
It is an arithmetic number, because the mean of its divisors is an integer number (67125872880).
Almost surely, 21320234412335 is an apocalyptic number.
1320234412335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1320234412335 is a deficient number, since it is larger than the sum of its proper divisors (827793519825).
1320234412335 is a wasteful number, since it uses less digits than its factorization.
1320234412335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6164239.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 1320234412335 its reverse (5332144320231), we get a palindrome (6652378732566).
The spelling of 1320234412335 in words is "one trillion, three hundred twenty billion, two hundred thirty-four million, four hundred twelve thousand, three hundred thirty-five".
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