Base | Representation |
---|---|
bin | 1100000000011111010101… |
… | …0011100101010011010111 |
3 | 1201202011002102011021120022 |
4 | 3000013311103211103113 |
5 | 3212302310303131210 |
6 | 44025100123055355 |
7 | 2531565332546450 |
oct | 300076523452327 |
9 | 51664072137508 |
10 | 13202550052055 |
11 | 4230196350831 |
12 | 15928ab37155b |
13 | 749cc23aca20 |
14 | 339014a66127 |
15 | 17d666922155 |
hex | c01f54e54d7 |
13202550052055 has 64 divisors (see below), whose sum is σ = 19950065780736. Its totient is φ = 8165344320000.
The previous prime is 13202550051991. The next prime is 13202550052073. The reversal of 13202550052055 is 55025005520231.
13202550052055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13202550052055 - 26 = 13202550051991 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2615900 + ... + 5766110.
It is an arithmetic number, because the mean of its divisors is an integer number (311719777824).
Almost surely, 213202550052055 is an apocalyptic number.
13202550052055 is a deficient number, since it is larger than the sum of its proper divisors (6747515728681).
13202550052055 is a wasteful number, since it uses less digits than its factorization.
13202550052055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3150448.
The product of its (nonzero) digits is 75000, while the sum is 35.
Adding to 13202550052055 its reverse (55025005520231), we get a palindrome (68227555572286).
The spelling of 13202550052055 in words is "thirteen trillion, two hundred two billion, five hundred fifty million, fifty-two thousand, fifty-five".
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