Base | Representation |
---|---|
bin | 1100000000011111010110… |
… | …0000000001011101010000 |
3 | 1201202011002122021221212220 |
4 | 3000013311200001131100 |
5 | 3212302312122004404 |
6 | 44025100321021040 |
7 | 2531565402351051 |
oct | 300076540013520 |
9 | 51664078257786 |
10 | 13202553313104 |
11 | 4230198178911 |
12 | 15928b0484780 |
13 | 749cc2c8213c |
14 | 339015274728 |
15 | 17d666d684d9 |
hex | c01f5801750 |
13202553313104 has 40 divisors (see below), whose sum is σ = 34351967270880. Its totient is φ = 4369190302848.
The previous prime is 13202553313087. The next prime is 13202553313151. The reversal of 13202553313104 is 40131335520231.
It is a super-2 number, since 2×132025533131042 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 989393307 + ... + 989406650.
It is an arithmetic number, because the mean of its divisors is an integer number (858799181772).
Almost surely, 213202553313104 is an apocalyptic number.
It is an amenable number.
13202553313104 is an abundant number, since it is smaller than the sum of its proper divisors (21149413957776).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202553313104 is a wasteful number, since it uses less digits than its factorization.
13202553313104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1978800107 (or 1978800101 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13202553313104 its reverse (40131335520231), we get a palindrome (53333888833335).
The spelling of 13202553313104 in words is "thirteen trillion, two hundred two billion, five hundred fifty-three million, three hundred thirteen thousand, one hundred four".
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