Base | Representation |
---|---|
bin | 11000100101111001… |
… | …01101011010110011 |
3 | 1021002010102001121112 |
4 | 30102330231122303 |
5 | 204014404301301 |
6 | 10022033543535 |
7 | 645115001042 |
oct | 142274553263 |
9 | 37063361545 |
10 | 13202806451 |
11 | 566570499a |
12 | 2685714bab |
13 | 13253cc513 |
14 | 8d367c559 |
15 | 5241629bb |
hex | 312f2d6b3 |
13202806451 has 2 divisors, whose sum is σ = 13202806452. Its totient is φ = 13202806450.
The previous prime is 13202806399. The next prime is 13202806457. The reversal of 13202806451 is 15460820231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13202806451 is a prime.
It is not a weakly prime, because it can be changed into another prime (13202806457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601403225 + 6601403226.
It is an arithmetic number, because the mean of its divisors is an integer number (6601403226).
Almost surely, 213202806451 is an apocalyptic number.
13202806451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202806451 is an equidigital number, since it uses as much as digits as its factorization.
13202806451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
The spelling of 13202806451 in words is "thirteen billion, two hundred two million, eight hundred six thousand, four hundred fifty-one".
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