Base | Representation |
---|---|
bin | 10011001101101000000… |
… | …000110101111100101111 |
3 | 11200012220222101212121221 |
4 | 103031220000311330233 |
5 | 133112433300330221 |
6 | 2450312031204211 |
7 | 164250156633001 |
oct | 23155000657457 |
9 | 4605828355557 |
10 | 1320300011311 |
11 | 469a32a33146 |
12 | 193a71976667 |
13 | 976719a5058 |
14 | 47c8d648371 |
15 | 245261a3541 |
hex | 13368035f2f |
1320300011311 has 2 divisors, whose sum is σ = 1320300011312. Its totient is φ = 1320300011310.
The previous prime is 1320300011267. The next prime is 1320300011411. The reversal of 1320300011311 is 1131100030231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1320300011311 - 213 = 1320300003119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320300011011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660150005655 + 660150005656.
It is an arithmetic number, because the mean of its divisors is an integer number (660150005656).
Almost surely, 21320300011311 is an apocalyptic number.
1320300011311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320300011311 is an equidigital number, since it uses as much as digits as its factorization.
1320300011311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1320300011311 its reverse (1131100030231), we get a palindrome (2451400041542).
The spelling of 1320300011311 in words is "one trillion, three hundred twenty billion, three hundred million, eleven thousand, three hundred eleven".
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