Base | Representation |
---|---|
bin | 11000100101111011… |
… | …00001101010001111 |
3 | 1021002010210221010201 |
4 | 30102331201222033 |
5 | 204014433123211 |
6 | 10022042314331 |
7 | 645116551636 |
oct | 142275415217 |
9 | 37063727121 |
10 | 13203020431 |
11 | 5665840737 |
12 | 26857b89a7 |
13 | 1325475a33 |
14 | 8d36d651d |
15 | 5241a60c1 |
hex | 312f61a8f |
13203020431 has 2 divisors, whose sum is σ = 13203020432. Its totient is φ = 13203020430.
The previous prime is 13203020423. The next prime is 13203020473. The reversal of 13203020431 is 13402030231.
It is a weak prime.
It is an emirp because it is prime and its reverse (13402030231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13203020431 - 23 = 13203020423 is a prime.
It is a super-2 number, since 2×132030204312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13203020399 and 13203020408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13203420431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601510215 + 6601510216.
It is an arithmetic number, because the mean of its divisors is an integer number (6601510216).
Almost surely, 213203020431 is an apocalyptic number.
13203020431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13203020431 is an equidigital number, since it uses as much as digits as its factorization.
13203020431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13203020431 its reverse (13402030231), we get a palindrome (26605050662).
The spelling of 13203020431 in words is "thirteen billion, two hundred three million, twenty thousand, four hundred thirty-one".
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