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1320311310233 is a prime number
BaseRepresentation
bin10011001101101000101…
…011111100011110011001
311200012221202122220211112
4103031220223330132121
5133112444143411413
62450313113310105
7164250354652316
oct23155053743631
94605852586745
101320311310233
11469a393501a3
12193a75705335
139767412cbc6
1447c90d49d0d
15245271862a8
hex13368afc799

1320311310233 has 2 divisors, whose sum is σ = 1320311310234. Its totient is φ = 1320311310232.

The previous prime is 1320311310209. The next prime is 1320311310277. The reversal of 1320311310233 is 3320131130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1308845826304 + 11465483929 = 1144048^2 + 107077^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320311310233 - 26 = 1320311310169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320311310199 and 1320311310208.

It is not a weakly prime, because it can be changed into another prime (1320311310433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660155655116 + 660155655117.

It is an arithmetic number, because the mean of its divisors is an integer number (660155655117).

Almost surely, 21320311310233 is an apocalyptic number.

It is an amenable number.

1320311310233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320311310233 is an equidigital number, since it uses as much as digits as its factorization.

1320311310233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1320311310233 its reverse (3320131130231), we get a palindrome (4640442440464).

The spelling of 1320311310233 in words is "one trillion, three hundred twenty billion, three hundred eleven million, three hundred ten thousand, two hundred thirty-three".