Base | Representation |
---|---|
bin | 11110000001010011101010… |
… | …101001100001011011011011 |
3 | 122022111001200112022021210211 |
4 | 132001103222221201123123 |
5 | 114301144430221314121 |
6 | 1144450151012551551 |
7 | 36544640666046403 |
oct | 3601235251413333 |
9 | 568431615267724 |
10 | 132031231432411 |
11 | 39084149107483 |
12 | 129846543225b7 |
13 | 588965135ca7c |
14 | 24864ba849803 |
15 | 103e67e348ce1 |
hex | 7814eaa616db |
132031231432411 has 2 divisors, whose sum is σ = 132031231432412. Its totient is φ = 132031231432410.
The previous prime is 132031231432409. The next prime is 132031231432481. The reversal of 132031231432411 is 114234132130231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132031231432411 - 21 = 132031231432409 is a prime.
It is a super-2 number, since 2×1320312314324112 (a number of 29 digits) contains 22 as substring.
Together with 132031231432409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132031231432481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66015615716205 + 66015615716206.
It is an arithmetic number, because the mean of its divisors is an integer number (66015615716206).
Almost surely, 2132031231432411 is an apocalyptic number.
132031231432411 is a deficient number, since it is larger than the sum of its proper divisors (1).
132031231432411 is an equidigital number, since it uses as much as digits as its factorization.
132031231432411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 132031231432411 its reverse (114234132130231), we get a palindrome (246265363562642).
The spelling of 132031231432411 in words is "one hundred thirty-two trillion, thirty-one billion, two hundred thirty-one million, four hundred thirty-two thousand, four hundred eleven".
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