1320312432031 has 4 divisors (see below), whose sum is σ = 1348404185952. Its totient is φ = 1292220678112.

The previous prime is 1320312432011. The next prime is 1320312432067. The reversal of 1320312432031 is 1302342130231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320312432031 is a prime.

It is a super-2 number, since 2×1320312432031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320312431987 and 1320312432005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320312432011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14045876890 + ... + 14045876983.

It is an arithmetic number, because the mean of its divisors is an integer number (337101046488).

Almost surely, 2^{1320312432031} is an apocalyptic number.

1320312432031 is a deficient number, since it is larger than the sum of its proper divisors (28091753921).

1320312432031 is an equidigital number, since it uses as much as digits as its factorization.

1320312432031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28091753920.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1320312432031 its reverse (1302342130231), we get a palindrome (2622654562262).

The spelling of 1320312432031 in words is "one trillion, three hundred twenty billion, three hundred twelve million, four hundred thirty-two thousand, thirty-one".