Base | Representation |
---|---|
bin | 11110000001010011111011… |
… | …011011110001010111010101 |
3 | 122022111002102011012110021011 |
4 | 132001103323123301113111 |
5 | 114301201014314242331 |
6 | 1144450234552452221 |
7 | 36544650655504645 |
oct | 3601237333612725 |
9 | 568432364173234 |
10 | 132031513040341 |
11 | 39084283069702 |
12 | 129847126aa071 |
13 | 58896977bb295 |
14 | 2486505dd2525 |
15 | 103e698e233b1 |
hex | 7814fb6f15d5 |
132031513040341 has 2 divisors, whose sum is σ = 132031513040342. Its totient is φ = 132031513040340.
The previous prime is 132031513040311. The next prime is 132031513040351. The reversal of 132031513040341 is 143040315130231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124762309787025 + 7269203253316 = 11169705^2 + 2696146^2 .
It is a cyclic number.
It is not a de Polignac number, because 132031513040341 - 217 = 132031512909269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132031513040311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66015756520170 + 66015756520171.
It is an arithmetic number, because the mean of its divisors is an integer number (66015756520171).
Almost surely, 2132031513040341 is an apocalyptic number.
It is an amenable number.
132031513040341 is a deficient number, since it is larger than the sum of its proper divisors (1).
132031513040341 is an equidigital number, since it uses as much as digits as its factorization.
132031513040341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132031513040341 its reverse (143040315130231), we get a palindrome (275071828170572).
The spelling of 132031513040341 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred thirteen million, forty thousand, three hundred forty-one".
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