Base | Representation |
---|---|
bin | 11110000001010100100101… |
… | …100101000110101100000011 |
3 | 122022111011020102201022222221 |
4 | 132001110211211012230003 |
5 | 114301203441323130201 |
6 | 1144450433052111511 |
7 | 36545004332614663 |
oct | 3601244545065403 |
9 | 568434212638887 |
10 | 132032220130051 |
11 | 3908460621066a |
12 | 1298488b465597 |
13 | 588977b140667 |
14 | 2486571c941a3 |
15 | 103e6db0464a1 |
hex | 781525946b03 |
132032220130051 has 2 divisors, whose sum is σ = 132032220130052. Its totient is φ = 132032220130050.
The previous prime is 132032220130037. The next prime is 132032220130067. The reversal of 132032220130051 is 150031022230231.
It is a weak prime.
It is an emirp because it is prime and its reverse (150031022230231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132032220130051 - 221 = 132032218032899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132032220129998 and 132032220130025.
It is not a weakly prime, because it can be changed into another prime (132032220130751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016110065025 + 66016110065026.
It is an arithmetic number, because the mean of its divisors is an integer number (66016110065026).
Almost surely, 2132032220130051 is an apocalyptic number.
132032220130051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132032220130051 is an equidigital number, since it uses as much as digits as its factorization.
132032220130051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 132032220130051 its reverse (150031022230231), we get a palindrome (282063242360282).
The spelling of 132032220130051 in words is "one hundred thirty-two trillion, thirty-two billion, two hundred twenty million, one hundred thirty thousand, fifty-one".
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