Base | Representation |
---|---|
bin | 1100000000100001110111… |
… | …1010000111001111110000 |
3 | 1201202012211212221021101220 |
4 | 3000020131322013033300 |
5 | 3212310204144204300 |
6 | 44025251455225040 |
7 | 2531621243553600 |
oct | 300103572071760 |
9 | 51665755837356 |
10 | 13203231241200 |
11 | 4230505912270 |
12 | 1592a5b518180 |
13 | 74a0a0564020 |
14 | 33907b304c00 |
15 | 17d6a662ada0 |
hex | c021de873f0 |
13203231241200 has 2880 divisors, whose sum is σ = 61322755092480. Its totient is φ = 2384557056000.
The previous prime is 13203231241177. The next prime is 13203231241201. The reversal of 13203231241200 is 214213230231.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13203231241201) by changing a digit.
It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 356844087582 + ... + 356844087618.
It is an arithmetic number, because the mean of its divisors is an integer number (21292623296).
Almost surely, 213203231241200 is an apocalyptic number.
13203231241200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13203231241200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30661377546240).
13203231241200 is an abundant number, since it is smaller than the sum of its proper divisors (48119523851280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13203231241200 is a wasteful number, since it uses less digits than its factorization.
13203231241200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201 (or 109 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13203231241200 its reverse (214213230231), we get a palindrome (13417444471431).
It can be divided in two parts, 13203231 and 241200, that added together give a palindrome (13444431).
The spelling of 13203231241200 in words is "thirteen trillion, two hundred three billion, two hundred thirty-one million, two hundred forty-one thousand, two hundred".
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