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132032511239623 is a prime number
BaseRepresentation
bin11110000001010100110110…
…111011100110010111000111
3122022111011222201111020020221
4132001110312323212113013
5114301210040334131443
61144450522011405211
736545014466165641
oct3601246673462707
9568434881436227
10132032511239623
1139084745572595
1212984950a53807
1358897c6547947
14248659c7d1891
15103e70689aeed
hex781536ee65c7

132032511239623 has 2 divisors, whose sum is σ = 132032511239624. Its totient is φ = 132032511239622.

The previous prime is 132032511239581. The next prime is 132032511239633. The reversal of 132032511239623 is 326932115230231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132032511239623 is a prime.

It is a super-3 number, since 3×1320325112396233 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132032511239623.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032511239633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016255619811 + 66016255619812.

It is an arithmetic number, because the mean of its divisors is an integer number (66016255619812).

Almost surely, 2132032511239623 is an apocalyptic number.

132032511239623 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032511239623 is an equidigital number, since it uses as much as digits as its factorization.

132032511239623 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 349920, while the sum is 43.

Adding to 132032511239623 its reverse (326932115230231), we get a palindrome (458964626469854).

The spelling of 132032511239623 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred eleven million, two hundred thirty-nine thousand, six hundred twenty-three".