Base | Representation |
---|---|
bin | 11110000001010101100111… |
… | …001001010010110101101011 |
3 | 122022111021002002120102112121 |
4 | 132001111213021102311223 |
5 | 114301213214423323133 |
6 | 1144451134145052111 |
7 | 36545043520534354 |
oct | 3601254711226553 |
9 | 568437062512477 |
10 | 132033320136043 |
11 | 3908502012a427 |
12 | 12984b37927037 |
13 | 58898c4cc3c91 |
14 | 2486637dd4d2b |
15 | 103e7528ce02d |
hex | 781567252d6b |
132033320136043 has 2 divisors, whose sum is σ = 132033320136044. Its totient is φ = 132033320136042.
The previous prime is 132033320135989. The next prime is 132033320136131. The reversal of 132033320136043 is 340631023330231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132033320136043 is a prime.
It is a super-2 number, since 2×1320333201360432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132033320136643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016660068021 + 66016660068022.
It is an arithmetic number, because the mean of its divisors is an integer number (66016660068022).
Almost surely, 2132033320136043 is an apocalyptic number.
132033320136043 is a deficient number, since it is larger than the sum of its proper divisors (1).
132033320136043 is an equidigital number, since it uses as much as digits as its factorization.
132033320136043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 34.
Adding to 132033320136043 its reverse (340631023330231), we get a palindrome (472664343466274).
The spelling of 132033320136043 in words is "one hundred thirty-two trillion, thirty-three billion, three hundred twenty million, one hundred thirty-six thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •