Search a number
-
+
1320340143130 = 25557237044909
BaseRepresentation
bin10011001101101010011…
…001111011110000011010
311200020000202220210010121
4103031222121323300122
5133113024034040010
62450320023303454
7164251155020251
oct23155231736032
94606022823117
101320340143130
11469a53653838
12193a832aab8a
139767a0b68a8
1447c94ad3798
152452997e3da
hex1336a67bc1a

1320340143130 has 16 divisors (see below), whose sum is σ = 2380879076040. Its totient is φ = 527187875392.

The previous prime is 1320340143107. The next prime is 1320340143193. The reversal of 1320340143130 is 313410430231.

It can be written as a sum of positive squares in 4 ways, for example, as 321014029561 + 999326113569 = 566581^2 + 999663^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1320340143095 and 1320340143104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118516885 + ... + 118528024.

Almost surely, 21320340143130 is an apocalyptic number.

1320340143130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1320340143130 is a deficient number, since it is larger than the sum of its proper divisors (1060538932910).

1320340143130 is a wasteful number, since it uses less digits than its factorization.

1320340143130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237045473.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1320340143130 its reverse (313410430231), we get a palindrome (1633750573361).

The spelling of 1320340143130 in words is "one trillion, three hundred twenty billion, three hundred forty million, one hundred forty-three thousand, one hundred thirty".

Divisors: 1 2 5 10 557 1114 2785 5570 237044909 474089818 1185224545 2370449090 132034014313 264068028626 660170071565 1320340143130