Base | Representation |
---|---|
bin | 1100000000100100110010… |
… | …0000110100100010010001 |
3 | 1201202021212101012212001220 |
4 | 3000021030200310202101 |
5 | 3212313304330440423 |
6 | 44025501230115253 |
7 | 2531646516600345 |
oct | 300111440644221 |
9 | 51667771185056 |
10 | 13204013140113 |
11 | 423087720a514 |
12 | 159303934bb29 |
13 | 74a196549bc3 |
14 | 3391130bb625 |
15 | 17d7000c99e3 |
hex | c024c834891 |
13204013140113 has 48 divisors (see below), whose sum is σ = 18494635627776. Its totient is φ = 8378622616320.
The previous prime is 13204013140099. The next prime is 13204013140127. The reversal of 13204013140113 is 31104131040231.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13204013140099) and next prime (13204013140127).
It is not a de Polignac number, because 13204013140113 - 28 = 13204013139857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13204013142113) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 268475181 + ... + 268524357.
It is an arithmetic number, because the mean of its divisors is an integer number (385304908912).
Almost surely, 213204013140113 is an apocalyptic number.
It is an amenable number.
13204013140113 is a deficient number, since it is larger than the sum of its proper divisors (5290622487663).
13204013140113 is a wasteful number, since it uses less digits than its factorization.
13204013140113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50054 (or 50031 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 13204013140113 its reverse (31104131040231), we get a palindrome (44308144180344).
The spelling of 13204013140113 in words is "thirteen trillion, two hundred four billion, thirteen million, one hundred forty thousand, one hundred thirteen".
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