Base | Representation |
---|---|
bin | 111101011111000111… |
… | …0001111101110010111 |
3 | 110121211010100112121210 |
4 | 1322332032033232113 |
5 | 4130404322034333 |
6 | 140354124312503 |
7 | 12353041042242 |
oct | 1727616175627 |
9 | 417733315553 |
10 | 132040424343 |
11 | 50aa8417143 |
12 | 217100a2733 |
13 | c5b3833909 |
14 | 6568488259 |
15 | 367c05da63 |
hex | 1ebe38fb97 |
132040424343 has 8 divisors (see below), whose sum is σ = 176366608128. Its totient is φ = 87870595064.
The previous prime is 132040424309. The next prime is 132040424393. The reversal of 132040424343 is 343424040231.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132040424343 - 217 = 132040293271 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132040424343.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132040424393) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39086655 + ... + 39090032.
It is an arithmetic number, because the mean of its divisors is an integer number (22045826016).
Almost surely, 2132040424343 is an apocalyptic number.
132040424343 is a deficient number, since it is larger than the sum of its proper divisors (44326183785).
132040424343 is an equidigital number, since it uses as much as digits as its factorization.
132040424343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78177253.
The product of its (nonzero) digits is 27648, while the sum is 30.
Adding to 132040424343 its reverse (343424040231), we get a palindrome (475464464574).
The spelling of 132040424343 in words is "one hundred thirty-two billion, forty million, four hundred twenty-four thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 1.005 sec. • engine limits •