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13204050514142 = 26602025257071
BaseRepresentation
bin1100000000100100111010…
…1111011001000011011110
31201202021221222112122121012
43000021032233121003132
53212313343412423032
644025505043135222
72531650452350465
oct300111657310336
951667858478535
1013204050514142
114230896317144
121593049974512
1374a1a1204407
143391180499dc
1517d70350d6b2
hexc024ebd90de

13204050514142 has 4 divisors (see below), whose sum is σ = 19806075771216. Its totient is φ = 6602025257070.

The previous prime is 13204050514139. The next prime is 13204050514177. The reversal of 13204050514142 is 24141505040231.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×132040505141422 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13204050514099 and 13204050514108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3301012628534 + ... + 3301012628537.

It is an arithmetic number, because the mean of its divisors is an integer number (4951518942804).

Almost surely, 213204050514142 is an apocalyptic number.

13204050514142 is a deficient number, since it is larger than the sum of its proper divisors (6602025257074).

13204050514142 is an equidigital number, since it uses as much as digits as its factorization.

13204050514142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6602025257073.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 13204050514142 its reverse (24141505040231), we get a palindrome (37345555554373).

The spelling of 13204050514142 in words is "thirteen trillion, two hundred four billion, fifty million, five hundred fourteen thousand, one hundred forty-two".

Divisors: 1 2 6602025257071 13204050514142