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132041314222 = 266020657111
BaseRepresentation
bin111101011111001000…
…1101000111110101110
3110121211012000202022021
41322332101220332232
54130410034023342
6140354155340354
712353051436526
oct1727621507656
9417735022267
10132041314222
1150aa8974784
12217104516ba
13c5b3a8597c
14656863a686
15367c187567
hex1ebe468fae

132041314222 has 4 divisors (see below), whose sum is σ = 198061971336. Its totient is φ = 66020657110.

The previous prime is 132041314211. The next prime is 132041314231. The reversal of 132041314222 is 222413140231.

132041314222 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1320413142222 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33010328554 + ... + 33010328557.

It is an arithmetic number, because the mean of its divisors is an integer number (49515492834).

Almost surely, 2132041314222 is an apocalyptic number.

132041314222 is a deficient number, since it is larger than the sum of its proper divisors (66020657114).

132041314222 is an equidigital number, since it uses as much as digits as its factorization.

132041314222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66020657113.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132041314222 its reverse (222413140231), we get a palindrome (354454454453).

The spelling of 132041314222 in words is "one hundred thirty-two billion, forty-one million, three hundred fourteen thousand, two hundred twenty-two".

Divisors: 1 2 66020657111 132041314222